Q1GATE 2022MCQ

For the following circuit with an ideal OPAMP, the difference between the maximum and the minimum values of the capacitor voltage ( $V_c$ ) is __________.

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📖 Explanation

When,

\begin{aligned} V_0&=+15V\\ V^+&=\frac{R}{3R} \times 15=5V\\ V_{cmax}&=5V \end{aligned}

When,

\begin{aligned} V_0&=-12V\\ V^+&=\frac{2R}{3R} \times (-12)=5V\\ V_{cmin}&=-8V \end{aligned}

$V_{cmax}=V_{cmin}=5-(-8)=13V$

Q2GATE 2016NAT

In the astable multivibrator circuit shown in the figure, the frequency of oscillation (in kHz) at the output pin 3 is __________

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📖 Explanation

\begin{array}{c} f=\frac{1}{0.69\left(R_{A}+2 R_{B}\right) C} \\ =\frac{1}{0.69\left(2.2 \times 10^{3}+2 \times 4.7 \times 10^{3}\right) \times 0.022 \times 10^{-6}} \\ =5.6818 \mathrm{kHz} \end{array}

Q3GATE 2009MCQ

In the following a stable multivibrator circuit, which properties of $v_{0}(t)$ depend on $R_2$ ?

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Q4GATE 2008MCQ

Consider the Schmidt trigger circuit shown below. A triangular wave which goes from -12 to 12 V is applied to the inverting input of OPMAP. Assume that the output of the OPAMP swings from +15 V to -15 V. The voltage at the non-inverting input switches between

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📖 Explanation

\begin{aligned} \frac{15-V_{1}}{10}+\frac{V_{0}-V_{1}}{10}&=\frac{V_{1}-(-15)}{10} \\ 15-V_{1}+V_{0}-V_{1}&=V_{1}+15 \\ \Rightarrow \quad V_{1}&=\frac{V_{0}}{3} \end{aligned}

since, $V_{0}$ swings from $-15 \vee$ to +15 V, Therefore, $V_{1}$ switches between $-5 \vee \text{ and } +5 \mathrm{V}$

Q5GATE 2008MCQ

An astable multivibrator circuit using IC 555 timer is shown below. Assume that the circuit is oscillating steadily. The voltage $V_c$ across the capacitor varies between

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📖 Explanation

$V_{C}$ varies between 3V to 5V.

Q6GATE 2005MCQ

Given the ideal operational amplifier circuit shown in the figure indicate the correct transfer characteristics assuming ideal diodes with zero cut-in voltage.

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📖 Explanation

$V_{u t}=\beta_{u} V_{\text {sat }}$ When lower diode is ON

\begin{aligned} \beta_{u}&=\frac{2 k \Omega}{2.5 \mathrm{k} \Omega} \\ \therefore \quad V_{u t}&=\frac{2}{2.5} \times 10=8 \mathrm{V} \\ V_{l t}&=-\beta_{l} V_{s a t} \end{aligned}

(when upper diode is ON, $\beta_{l}=\frac{2 \mathrm{k} \Omega}{4 \mathrm{k} \Omega}=\frac{1}{2})$ $=-\frac{1}{2} \times 10=-5 \mathrm{V}$ $V_{u t} \& V_{l t}$ are upper and lower transition voltage.

Q7GATE 2001MCQ

Consider the following two statements: Statement 1: A stable multi-vibrator can be used for generating square wave. Statement 2: B stable multi-vibrator can be used for storing binary information.

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