Q1GATE 2023MCQ

In the circuit shown below, $V_{1}$ and $V_{2}$ are bias voltages. Based on input and output impedances, the circuit behaves as a

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📖 Explanation

Here from circuit, $M_{1}$ is common-gate amplifier and $M_{2}$ behaves as an active load. By using properties of common gate (CG) amplifier, Input impedance $\left(R_{i}\right)$ is low Output impedance $\left(R_{0}\right)$ is high So, it is a current amplifier. Current amplifier is a current controlled current source.

Q2GATE 2018MCQ

A good transimpedance amplifier has

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Q3GATE 2017MCQ

A good transconductance amplifier should have

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Q4GATE 2014MCQ

In the ac equivalent circuit shown in the figure, if $i_{\in}$ is the input current and $R_{F}$ is very larger, the type of feedback is

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📖 Explanation

Sampling $\rightarrow$ current Mixing $\rightarrow$ voltage

Q5GATE 2014MCQ

The feedback topology in the amplifier circuit ( the base bias circuit is not shown for simplicity) in the figure is

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📖 Explanation

The feedback topology in the amplifier circuit is current series because Sampling $\rightarrow$ Current Mixing $\rightarrow$ Series So current-series feedback

Q6GATE 2014MCQ

The desirable characteristics of a transconductance amplifier are

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Q7GATE 2013MCQ

In a voltage-voltage feedback as shown below, which one of the following statements is TRUE if the gain k is increased?

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📖 Explanation

The given configuration is a voltage-series feedback configuration. So, the input impedance increases $R_{i f}=R_{i}\left(1+A_{0} K\right)$ and, the output impedance decreases $R_{o f}=\frac{R_{o}}{1+A_{o} K}$

Q8GATE 2007MCQ

In a transconductance amplifier, it is desirable to have

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Q9GATE 2006MCQ

The input impedance ( $Z_{i}$ ) and the output impedance ( $Z_{0}$ ) of an ideal transconductance (voltage controlled current source) amplifier are

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Q10GATE 2005MCQ

The effect of current shunt feedback in an amplifier is to

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Q11GATE 2004MCQ

Voltage series feedback (also called series-shunt feedback) results in

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Q12GATE 2003MCQ

An amplifier without feedback has a voltage gain of 50, input resistance of 1 k $\Omega$ and output resistance of 2.5 k $\Omega$ . The input resistance of the current-shunt negative feedback amplifier using the above amplifier with a feedback factor of 0.2, is

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📖 Explanation

In current shunt negative feedback amplifier. $R_{i f}=\frac{R_{i}}{1+A \beta} ; R_{i f}=\frac{1 \times 10^{3}}{1+50 \times 0.2}=\frac{10^{3}}{1+10}$ $R_{i f}=\frac{1}{11} k \Omega$

Q13GATE 2002MCQ

In a negative feedback amplifier using voltage-series (i.e. voltage-sampling series mixing) feedback. (Ri and Ro denote the input and output resistance respectively)

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📖 Explanation

$R_{i}$ increases by factor of $1+A \beta$ and $R_{0}$ decreases by $1+A \beta$

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