📖 Explanation
(i) 80 buses with 2 axle with 40 kN each. N1=80×2=160 L1=40kN
160 truks{Front axle→40kNRear axle→80kN
N1=160,L1=40kN N2=160,L2=80kN
Total no. of repetitions{For40kN=160+160=320For80kN=160
N1=320,L1=40kN N2=160,L2=80kN As per 4th power law
Ns=N1(L5L1)4+N2(L5L2)4=320(8040)4+160(8080)4=20+160=180