📖 Explanation
Given that,
h1(t)h2(t)=2δ(t+2)−3δ(t+1)=δ(t−2)
Overall impulse response is,
h(t)=h1(t)+h2(t)=2δ(t+2)−3δ(t+1)+δ(t−2)
If input, x(t)=u(t) , then the output will be,
y(t)=x(t)∗h(t)=u(t)∗[2δ(t+2)−3δ(t+1)δ(t−2)]=2u(t+2)−3u(t+1)+u(t−2)
By plotting y(t), we get, The energy of y(t) can be given as, Ey=∫−∞∞y2(t)dt By plotting y2(t) , we get, Ey=Area under the plot of y2(t)=(4×1)+(3×1)=7J