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GATE CE · Rcc Structures

Working Stress And Limit State Method Practice Questions

Generate GATE-level questions on Working Stress And Limit State Method in RCC Structures. Focus on core concepts, previous year patterns, and numerical problem-solving techniques.

58 questions · 20 PYQs · 0 AI practice · GATE CE 2027

Q21GATE 2015NAT

Consider the singly reinforced beam section given below (left figure). The stress block parameters for the cross-section from IS: 456 : 2000 are also given below (right figure). The moment of resistance for the given section by the limit state method is ________ kN-m

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📖 Explanation

\begin{aligned} A_{s t} &=4 \times \frac{\pi}{4} \times 12^{2} \\ &=452.38 \mathrm{mm}^{2} \\ x_{u, \lim } &=0.48 \times 300=144 \mathrm{mm} \\ \because \quad C &=T \\ \Rightarrow \quad 0.36 f_{c k} b x_{u} &=0.87 \mathrm{f}_{y} A_{s t} \\ \Rightarrow \quad x_{u}&=\frac{0.87 f_{y} A_{s t}}{0.36 f_{c k} b}=90.73 \mathrm{mm} \end{aligned}

$\because x_{u} \lt x_{u, l \mathrm{im}},$ it is under reinforced section

\begin{aligned} \Rightarrow \quad M O R&=0.36 f_{c k} b x_{u}\left(d-0.42 x_{u}\right) \\ &=42.7708 \times 10^{6} \mathrm{N}-\mathrm{mm} \\ &=42.7708 \mathrm{kN}-\mathrm{m} \end{aligned}

Q22

GATE 2015

MCQ

Workability of concrete can be measured using slump, compaction factor and Vebe time. Consider the following statements for workability of concrete: (i) As the slump increases, the Vebe time increases (ii) As the slump increases, the compaction factor increases Which of the following is TRUE?

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📖 Explanation

As slump increase, water content increases means workability increases. Compaction factor $=\frac{\text { Weight of partially compacted concrete }}{\text { Weight of fully compacted concrete }}$ $\therefore$ Compaction factor will also increase. The time required for complete remoulding in seconds is considered as a measure of workability and is expressed as the number of Vee-Bee seconds. $\therefore$ As workability increases, Vee-Bee time decreases.

Q23GATE 2015NAT

According to the concept of Limit State Design as per IS 456: 2000, the probability of failure of a structure is__________.

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📖 Explanation

The structure may fail when, the load exceeds the design load (ii) the strength is less than the characteristic strength (iii) both the load exceeds the design load and strength is less than the characteristic strength. The probability of load exceeding design load = 5% (iv) The probability of strength less than characteristic strength = 5% The probability of failure is $=0.05 \times 0.95+0.05 \times 0.95+0.05 \times 0.05$ $=0.0975$

Q24GATE 2015NAT

The composition of an air-entrained concrete is given below: Assume the specific gravity of OPC, sand and coarse aggregate top be 3.14, 2.67 and 2.74, respectively. The air content is ________ $litres/m^{3}$ .

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📖 Explanation

Let the total volume of air-entrained concrete is unity.

\begin{array}{c} \frac{M_{C}}{\rho_{C}}+\frac{M_{F A}}{\rho_{F A}}+\frac{M_{C A}}{\rho_{C A}}+V_{W}+V_{\mathrm{Air}}=1.0 \\ \frac{368}{3.14 \times 1000}+\frac{606}{2.67 \times 1000} \\ +\frac{1155}{2.74 \times 1000}+\frac{184}{1000}+V_{V}=1.0 \\ 0.11720+0.22697+0.42153 \\ \begin{aligned} +0.184+V_{v}&=1.0 \\ V_{V}&=0.0503 \\ V_{V}&=0.0503 \times 1000 \\ \quad&=50.3\; litres / \mathrm{m}^{3} \end{aligned} \end{array}

Q25GATE 2015MCQ

Consider the singly reinforced beam shown in the figure below: At cross-section XX, which of the following statements is TRUE at the limit state?

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📖 Explanation

Currently no explanation available

Explanation Figure 2

Q26GATE 2014MCQ

Group I contains representative stress-strain curves as shown in the figure, while Group II given the list of materials. Match the stress-strain curves with the corresponding materials.

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📖 Explanation

Currently no explanation available

Q27GATE 2014MCQ

The target means strength $f_{cm}$ for concrete mix design obtained from the characteristic strength $f_{ck}$ and standard deviation $\sigma$ , as defined in IS:456-2000, is

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📖 Explanation

Currently no explanation available

Q28GATE 2014NAT

The flexural tensile strength of M25 grade of concrete, in $N/mm^{2}$ , as per IS:456-2000 is

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📖 Explanation

$\text { Flexural strength }=0.7 \sqrt{f_{c k}}=3.5 \mathrm{N} / \mathrm{mm}^{2}$

Q29GATE 2014MCQ

The modulus of elasticity, $E=5000\sqrt{f_{ck}}$ where $f_{ck}$ is the characteristic compressive strength of concrete, specified in IS:456-2000 is based on

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📖 Explanation

In IS:456-2000, the modulus of elasticity of concrete is given by: $E = 5000 \sqrt{f_{ck}} \quad \text{(\in MPa)}$ This value is derived from the stress-strain curve of concrete and is defined as the secant modulus, which is the slope of the line joining the origin to a point on the stress-strain curve at working stress level (typically at 0.33 of ultimate strength).

Q30GATE 2014MCQ

The first moment of area about the axis of bending for a beam cross-section is

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📖 Explanation

Currently no explanation available

Q31GATE 2014MCQ

Match the information given in Group - I with those in Group - II.

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📖 Explanation

Currently no explanation available

Q32GATE 2014MCQ

In a reinforced concrete section, the stress at the extreme fibre in compression is 5.80 MPa. The depth of neutral axis in the section is 58 mm and the grade of concrete is M25. Assuming linear elastic behavior of the concrete, the effective curvature of the section (in per mm) is

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📖 Explanation

Modulus of elasticity of concrete.

\begin{aligned} E &=5000 \sqrt{25} \\ &=25000 \mathrm{N} / \mathrm{mm}^{2} \\ \therefore \quad \frac{M}{I} &=\frac{\sigma}{y}=\frac{E}{R} \\ \Rightarrow \quad \frac{1}{R} &=\frac{\sigma}{E y}=\frac{5.8}{E X_{u}} \\ \text { Curvature } &=\frac{5.8}{58 \times 25000} \\ &=4 \times 10^{-6} \text {Per } \mathrm{mm} \\ \Rightarrow \quad \text { Curvature }&=4 \times 10^{-6} \text {per } \mathrm{mm} \end{aligned}

Explanation Figure 1

Q33GATE 2014NAT

While designing, for a steel column of Fe250 grade, a base plate resting on a concrete pedestal of M20 grade, the bearing strength of concrete (in $N/mm^{2}$ ) in limit state method of design as per IS:456-2000 is ________________

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📖 Explanation

\begin{aligned} &\text { Permissible bearing stress } \\ &=0.45 \mathrm{f}_{\mathrm{ck}} \\ &=0.45 \times 20=9 \mathrm{N} / \mathrm{mm}^{2} \\ \end{aligned}

Q34GATE 2013MCQ

Maximum possible value of Compacting Factor for fresh (green) concrete is:

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📖 Explanation

Currently no explanation available

Q35GATE 2012MCQ

As per IS 456:2000, in the Limit State Design of a flexural member, the strain in reinforcing bars under tension at ultimate state should not be less than

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📖 Explanation

Currently no explanation available

Explanation Figure 1

Q36GATE 2011MCQ

The cross-section of a thermo-mechanically treated (TMT) reinforcing bar has

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📖 Explanation

Currently no explanation available

Q37GATE 2009MCQ

Column-I gives a list of test methods for evaluating properties of concrete and Column-II gives the list of properties. The correct match of the test with the property is

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📖 Explanation

P. Resonant frequency test is used to determine dynamic modulus of elasticity whereas destructive test like cube test etc measures the static modulus of elasticity. Q. Rebound hammer test is a non-destructive test used for compressive strength of concrete. R. Split cylinder test is used to determine the direct tensile strength of concrete. S. Compaction factor test is used to measure workability of concrete.

Q38GATE 2009MCQ

For limit state of collapse, the partial safety factors recommended by IS 456:2000 for estimating the design strength of concrete and reinforcing steel are respectively

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📖 Explanation

Currently no explanation available

Q39GATE 2009MCQ

The modulus of rupture of concrete in terms of its characteristic cube compressive strength ( $f_{ck}$ ) in MPa according to IS 456:2000 is

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📖 Explanation

Currently no explanation available

Q40GATE 2008MCQ

Un-factored maximum bending moment at a section of a reinforced concrete beam resulting form a frame analysis are 50, 80, 120 and 180 kNm under dead, live, wind and earthquake loads respectively. The design moment (kNm) as per IS:456-2000 for the limit state of collapse (flexure) is

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📖 Explanation

Wind and earthquake effects are not considered simultaneously. (i) Design moment when wind effect is considered

\begin{aligned} &=1.2(\mathrm{DL}+\mathrm{LL}+\mathrm{WL}) \\ &=1.2(50+80+120) \\ &=300 \mathrm{kN}-\mathrm{m} \end{aligned}

(ii) Design moment when earthquake effect is considered

\begin{aligned} &=1.2(\mathrm{DL}+\mathrm{LL}+\mathrm{EL}) \\ &=1.2(50+80+180) \\ &=372 \mathrm{kN}-\mathrm{m} \end{aligned}

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